Viktoria Plzen vs Ceske Budejovice Prediction: Plzen will extend their unbeaten run with a win

In round 19 of the Czech Fortuna Liga, Viktoria Plzen will welcome Ceske Budejovice to Doosan Arena. The previous time these two sides met, Viktoria Plzen pulled off a dominant win on the road. How will Ceske Budejovice approach this game?

Viktoria Plzen secured a hard-fought victory over Karvina the previous weekend and will hope for a similar outcome. In that game, this team went behind in the 14th minute, with Amar Memic putting their opponent in the lead. However, second-half late strikes from Pavel Sulc were enough to see this team take maximum points. In the meantime, Viktoria Plzen extended their unbeaten run with that victory, playing without a defeat in seven games, where they won five. Viktoria Plzen defeated Real Sociedad, Bohemians, Dynamo Kyiv, Janblonec, and Hradec Kralove in those games. This season in the league, Viktoria Plzen have 40 points from a possible 54, leaving them seated second.

Ceske Budejovice's last league game was against Mlada Boleslav, and they suffered a 0-4 defeat. In that encounter, Ceske Budejovice held their opponent to a draw at halftime until the second half, during which they struggled to show any strong defensive play. However, that defeat extended the visitors' winless run to nine, with their last win being a 0-4 encounter over Rudolfov in a friendly encounter. However, in that run, this team lost to Taborsko, Slavia Prague, Jablonec, Teplice, Hradec Kralove, and Karvina. Heading into this fixture, Ceske Budejovice accumulated three points from 18 matches, leaving them seated at the bottom of the standings. 

Viktoria Plzen will leave no chance for Ceske Budejovice in this game as they will look to boost their title league win with a solid performance. While Ceske Budejovice have the fewest points in the league and are the weakest side, I do not expect them to show any surprising play. Take Viktoria Plzen to win this game with many goals, while Ceske Budejovice fails to respond.